1.81=x^(1/2)+1.44x

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Solution for 1.81=x^(1/2)+1.44x equation: 


D( x )

x < 0

x < 0

x in <0:+oo)

1.81 = 1.44*x+x^(1/2) // - 1.44*x+x^(1/2)

1.81-(1.44*x)-x^(1/2) = 0

1.81-1.44*x-x^(1/2) = 0

t_1 = x^(1/2)

1.81-1.44*t_1^2-1*t_1^1 = 0

1.81-1.44*t_1^2-t_1 = 0

DELTA = (-1)^2-(-1.44*1.81*4)

DELTA = 11.4256

DELTA > 0

t_1 = (11.4256^(1/2)+1)/(-1.44*2) or t_1 = (1-11.4256^(1/2))/(-1.44*2)

t_1 = -0.34722222*(11.4256^(1/2)+1) or t_1 = -0.34722222*(1-11.4256^(1/2))

t_1 = -0.34722222*(11.4256^(1/2)+1)

x^(1/2)-(-0.34722222*(11.4256^(1/2)+1)) = 0

x^(1/2)+0.34722222*(11.4256^(1/2)+1) = 0

1*x^(1/2) = -(0.34722222*(11.4256^(1/2)+1)) // : 1

x^(1/2) = -0.34722222*(11.4256^(1/2)+1)

( -0.34722222*(11.4256^(1/2)+1) < 0 i 1/2 in (0:1) ) => x naleu017Cy do O

t_1 = -0.34722222*(1-11.4256^(1/2))

x^(1/2)-(-0.34722222*(1-11.4256^(1/2))) = 0

x^(1/2)+0.34722222*(1-11.4256^(1/2)) = 0

1*x^(1/2) = -(0.34722222*(1-11.4256^(1/2))) // : 1

x^(1/2) = -0.34722222*(1-11.4256^(1/2))

x^(1/2) = -0.34722222*(1-11.4256^(1/2)) // ^ 2

x = 0.34722222^2*(1-11.4256^(1/2))^2

x = 0.34722222^2*(1-11.4256^(1/2))^2

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